Match the transformation in column-I with appropriate options in column-II.
Column-I | Column-II | ||
(a) | CO2(s) ⎯→ CO2(g) | (p) | phase transition |
(b) | CaCO3(s) ⎯→ CaO(s) + CO2(g) | (q) | allotropic change |
(c) | 2H ⎯→ H2(g) | (r) | ΔH is positive |
(d) | P(white, solid) ⎯→ P(red, solid) | (s) | ΔS is positive |
(t) | ΔS is negative |
Text Solution
Verified by ExpertsA
(A – p, r, s) ; (B – r, s) ; (C – t) ; (D – p, q, t)
CO 2 (s) ⎯→ CO 2 (g)
It is phase transition. The process is endothermic (sublimation).
Gas is produced, so entropy increases.
On heating CaCO 3 decomposes. So, process is endothermic.
The entropy increases as gaseous product is formed.
2H 
⎯→ H 2 (g)
Entropy decreases as number of gaseous particles decreases.
It is phase transition.
White and red P are allotopes.
Red P is more stable than white. So Δ H is – ve.
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